Molto probabilmente perché hai impostato id="delete"
. Di solito i valori degli attributi id non sono duplicati.
echo "<td><form action='delete_prod.php' id='delete' method='get'>";
echo "<button type='submit' form = 'delete' class='btn btn-default' name='delete'>Delete</button>";
Il pulsante di invio ottiene il primo ID e quindi il primo input nascosto.
In alternativa, puoi concepire il tuo pulsante in questo modo e fungere da indicatore:
Non c'è bisogno di stampare ogni modulo!. Avvolgilo semplicemente con il tavolo:
echo "<form action='delete_prod.php' id='delete' method='get'>";
echo '<table>';
while($row = mysqli_fetch_assoc($result)) {
$prod_id = $row['prod_id'];
echo "<tr>";
echo "<td>".$count."</td>";
echo "<td>".$row['prod_id']."</td>";
echo "<td>".$row['prod_name']."</td>";
echo "<td>".$row['prod_price']."</td>";
echo "<td>";
// each id is assigned to each button, so that when its submitted you get the designated id, the one that you clicked
echo "<button type='submit' value='$prod_id' class='btn btn-default' name='delete'>Delete</button>";
echo "</td>";
echo '</tr>';
}
echo '</table>';
echo '</form>';
Quindi in elaborazione PHP:
if(isset($_GET['delete'])) // as usual
{
include "connection.php";
$prod_id = $_GET['delete']; // get the id
// USE PREPARED STATEMENTS!!!
$del="DELETE FROM products WHERE prod_id = ?";
$delete = $link->prepare($del);
$delete->bind_param('i', $prod_id);
$delete->execute();
// don't echo anything else, because you're going to use header
if($delete->affected_rows > 0) {
header('location:show_db.php');
} else {
echo 'Sorry delete did not push thru!';
}
}