Questa è una versione semplificata di @a_horse's correct rispondi
(dopo la discussione con OP nei commenti).
Funziona con qualsiasi (ragionevolmente finito) numero di livelli nella ricorsione.
Prezzo totale per project_id
specificato
WITH RECURSIVE cte AS (
SELECT project_id AS project_parent, project_value
FROM projects
WHERE project_id = 1 -- enter id of the base project here !
UNION ALL
SELECT p.project_id, p.project_value
FROM cte
JOIN projects p USING (project_parent)
)
SELECT sum(project_value) AS total_value
FROM cte;
Prezzo totale per tutti i progetti
WITH RECURSIVE cte AS (
SELECT project_id, project_id AS project_parent, project_value
FROM projects
WHERE project_parent IS NULL -- all base projects
UNION ALL
SELECT c.project_id, p.project_id, p.project_value
FROM cte c
JOIN projects p USING (project_parent)
)
SELECT project_id, sum(project_value) AS total_value
FROM cte
GROUP BY 1
ORDER BY 1;
db<>violino qui
(con test case corretto)
Vecchio sqlfiddle