Come ottenere e ordinare le voci più rilevanti dal database con più parole chiave Laravel 5

Va bene, forse qualche mago SQL potrebbe darti una soluzione SQL migliore. Ma fino ad allora...

È così che lo farei con Laravel raccolte (ordinamento con php):

$search_terms = array('York', 'North Yorkshire');

$properties = Property::where(function ($q) use ($search_terms) {
            foreach ($search_terms as $value) {
                $q->orWhere('address1', 'like', "%{$value}%");
                $q->orWhere('address2', 'like', "%{$value}%");
                $q->orWhere('postcode', 'like', "%{$value}%");
                $q->orWhere('city_town', 'like', "%{$value}%");
                $q->orWhere('county', 'like', "%{$value}%");
            }
        })->paginate(25);

$props = ['address1', 'address2', 'postcode', 'city_town', 'county'];

$properties = $properties->sortByDesc(function($i, $k) use ($search_terms, $props) {
    // The bigger the weight, the higher the record
    $weight = 0;
    // Iterate through search terms
    foreach($search_terms as $searchTerm) {
        // Iterate through properties (address1, address2...)
        foreach($props as $prop) { 
            // Use strpos instead of %value% (cause php)
            if(strpos($i->{$prop}, $searchTerm) !== false)
                $weight += 1; // Increase weight if the search term is found
        }
    }

    return $weight;
});

$properties = $properties->values()->all();