Che ne dici di combinare le tue due domande con un JOIN?
SQL:
SELECT
tbl1.key1, tbl1.key2, tbl1.info1, tbl1.info2, tbl1.serial_count, tbl1.serial_ids,
tbl2.product_data_count, tbl2.product_data_ids
FROM
(
select * , count(*) as serial_count,GROUP_CONCAT(key1,' ',key2) as serial_ids from
(
SELECT distinct
if(b.serial < 10,a.key1,null) AS `key1`,
if(b.serial < 10,a.key2,null) AS `key2`,
if(b.serial < 10,a.info1,null) AS `info1`,
if(b.serial < 10,a.info2,null) AS `info2`
FROM main_info a inner join product1 b on a.key1 = b.key1 AND a.key2= b.key2
) as sub group by info1,info2
) tbl1
LEFT OUTER JOIN
(
select * , count(*) as product_data_count,GROUP_CONCAT(key1,' ',key2) as product_data_ids from
(
SELECT distinct
if(b.product_data IS NOT NULL,a.key1,null) AS `key1`,
if(b.product_data IS NOT NULL,a.key2,null) AS `key2`,
if(b.product_data IS NOT NULL,a.info1,null) AS `info1`,
if(b.product_data IS NOT NULL,a.info2,null) AS `info2`
FROM main_info a inner join product1 b on a.key1 = b.key1 AND a.key2= b.key2
) as sub group by info1,info2
) tbl2
ON tbl1.info1 = tbl2.info1 AND tbl1.info2 = tbl2.info2
ORDER BY 3,4
;
Uscita:
mysql> SELECT
-> tbl1.key1, tbl1.key2, tbl1.info1, tbl1.info2, tbl1.serial_count, tbl1.serial_ids,
-> tbl2.product_data_count, tbl2.product_data_ids
-> FROM
-> (
-> select * , count(*) as serial_count,GROUP_CONCAT(key1,' ',key2) as serial_ids from
-> (
-> SELECT distinct
-> if(b.serial < 10,a.key1,null) AS `key1`,
-> if(b.serial < 10,a.key2,null) AS `key2`,
-> if(b.serial < 10,a.info1,null) AS `info1`,
-> if(b.serial < 10,a.info2,null) AS `info2`
-> FROM main_info a inner join product1 b on a.key1 = b.key1 AND a.key2= b.key2
-> ) as sub group by info1,info2
-> ) tbl1
-> LEFT OUTER JOIN
-> (
-> select * , count(*) as product_data_count,GROUP_CONCAT(key1,' ',key2) as product_data_ids from
-> (
-> SELECT distinct
-> if(b.product_data IS NOT NULL,a.key1,null) AS `key1`,
-> if(b.product_data IS NOT NULL,a.key2,null) AS `key2`,
-> if(b.product_data IS NOT NULL,a.info1,null) AS `info1`,
-> if(b.product_data IS NOT NULL,a.info2,null) AS `info2`
-> FROM main_info a inner join product1 b on a.key1 = b.key1 AND a.key2= b.key2
-> ) as sub group by info1,info2
-> ) tbl2
-> ON tbl1.info1 = tbl2.info1 AND tbl1.info2 = tbl2.info2
-> ORDER BY 3,4
-> ;
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
| key1 | key2 | info1 | info2 | serial_count | serial_ids | product_data_count | product_data_ids |
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
| NULL | NULL | NULL | NULL | 1 | NULL | NULL | NULL |
| 1 | 2 | 14 | 92 | 1 | 1 2 | 1 | 1 2 |
| 1 | 3 | 15 | 82 | 3 | 1 3,1 4,1 5 | 3 | 1 3,1 4,1 5 |
| 1 | 1 | 15 | 90 | 1 | 1 1 | 1 | 1 1 |
| 2 | 1 | 17 | 90 | 1 | 2 1 | 3 | 2 2,2 3,2 1 |
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
5 rows in set (0.01 sec)
mysql> select version();
+-----------------+
| version() |
+-----------------+
| 10.1.10-MariaDB |
+-----------------+
1 row in set (0.00 sec)
