Confronta più intervalli di date

Dopo un chiarimento nel commento.

Il tuo compito per come la intendo io:

Controlla tutti i individui forniti intervalli di date (filter ) se sono coperti dal combinato intervalli di date di serie di codici nella tabella (invoice ).

Può essere eseguito con un semplice SQL, ma non è un compito banale . I passaggi potrebbero essere:

1. Fornisci intervalli di date come filtri.

2. Combina gli intervalli di date in invoice tabella per codice.Può generare uno o più intervalli per codice.

3. Cerca le sovrapposizioni tra filtri e fatture combinate

4. Classificare:completamente coperto/parzialmente coperto.Può comportare una copertura completa, una o due coperture parziali o nessuna copertura.Ridurre al livello massimo di copertura.

5. Visualizza una riga per ogni combinazione di (filtro, codice) con la copertura risultante, in un ordinamento ragionevole

Intervalli di filtri ad hoc

WITH filter(filter_id, startdate, enddate) AS (
    VALUES
      (1, '2012-05-01'::date, '2012-06-05'::date) -- list filters here.
     ,(2, '2012-05-01', '2012-05-31')
     ,(3, '2012-06-01', '2012-06-30')
    )
SELECT * FROM filter;

Oppure mettili in una tabella (temporanea) e usa invece la tabella.

Combina intervalli di date sovrapposti/adiacenti per codice

WITH a AS (
    SELECT code, startdate, enddate
          ,max(enddate) OVER (PARTITION BY code ORDER BY startdate) AS max_end
-- Calculate the cumulative maximum end of the ranges sorted by start
    FROM   invoice
    ), b AS (
    SELECT *
          ,CASE WHEN lag(max_end) OVER (PARTITION BY code
                                        ORDER BY startdate) + 2 > startdate
-- Compare to the cumulative maximum end of the last row.
-- Only if there is a gap, start a new group. Therefore the + 2.
           THEN 0 ELSE 1 END AS step
    FROM   a
    ), c AS (
    SELECT code, startdate, enddate, max_end
          ,sum(step) OVER (PARTITION BY code ORDER BY startdate) AS grp
-- Members of the same date range end up in the same grp
-- If there is a gap, the grp number is incremented one step
    FROM   b
    )
SELECT code, grp
      ,min(startdate) AS startdate
      ,max(enddate) AS enddate
FROM   c
GROUP  BY 1, 2
ORDER  BY 1, 2

SELECT finale alternativa (potrebbe essere più veloce o meno, dovrai testare):

SELECT DISTINCT code, grp
          ,first_value(startdate) OVER w AS startdate
          ,last_value(enddate) OVER w AS enddate
FROM   c
WINDOW W AS (PARTITION BY code, grp ORDER BY startdate
             RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) 
ORDER  BY 1, 2;

Unisci a una query

WITH 
    -- supply one or more filter values
    filter(filter_id, startdate, enddate) AS (
    VALUES
      (1, '2012-05-01'::date, '2012-06-05'::date) -- cast values in first row
     ,(2, '2012-05-01', '2012-05-31')
     ,(3, '2012-06-01', '2012-06-30')
    )
    -- combine date ranges per code
    ,a AS (
    SELECT code, startdate, enddate
          ,max(enddate) OVER (PARTITION BY code ORDER BY startdate) AS max_end
    FROM   invoice
    ), b AS (
    SELECT *
          ,CASE WHEN (lag(max_end) OVER (PARTITION BY code ORDER BY startdate)
                      + 2) > startdate THEN 0 ELSE 1 END AS step
    FROM   a
    ), c AS (
    SELECT code, startdate, enddate, max_end
          ,sum(step) OVER (PARTITION BY code ORDER BY startdate) AS grp
    FROM   b
    ), i AS ( -- substitutes original invoice table
    SELECT code, grp
          ,min(startdate) AS startdate
          ,max(enddate) AS enddate
    FROM   c
    GROUP  BY 1, 2
    )
    -- match filters
    , x AS (
    SELECT f.filter_id, i.code
            ,bool_or(f.startdate >= i.startdate
              AND f.enddate   <= i.enddate) AS full_cover
    FROM   filter f
    JOIN   i ON i.enddate >= f.startdate
            AND i.startdate <= f.enddate -- only overlapping
    GROUP  BY 1,2
    )
SELECT f.*, i.code
      ,CASE x.full_cover
        WHEN TRUE  THEN 'fully covered'
        WHEN FALSE THEN 'partially covered'
        ELSE            'invoice missing'
       END AS covered
FROM   (SELECT DISTINCT code FROM i) i
CROSS  JOIN filter f -- all combinations of filter and code
LEFT   JOIN x USING (filter_id, code)    -- join in overlapping
ORDER  BY filter_id, code;

Testato e funziona per me su PostgreSQL 9.1.