Query Postgres complessa

Tutto quello che devi fare è eseguire una query aggregata:

select sum(t.export) as TotalExport,
sum(t.import) as TotalImport
FROM country c inner join Organization o on c.Country_Code = o.Country_Code
inner join Transaction t on o.organization_code = t.organization_code 

Ora ti chiedi:dov'è la colonna Corridoio? La risposta è:usa la funzione string_agg:

select string_agg(DISTINCT c.country, '-' ORDER BY c.country) as Corridor,
sum(t.export) as TotalExport,
sum(t.import) as TotalImport
FROM country c inner join Organization o on c.Country_Code = o.Country_Code
inner join Transaction t on o.organization_code = t.organization_code